Desicription
Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results.
Note: The input string may contain letters other than the parentheses ( and ).
Example 1:
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Input: "()())()"
Output: ["()()()", "(())()"]
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Example 2:
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Input: "(a)())()"
Output: ["(a)()()", "(a())()"]
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Example 3:
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Input: ")("
Output: [""]
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Solution
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class {
private:
bool isInvalid(const string& s) const {
int count = 0;
for(const auto& c : s) {
if(c == '(') {
count++;
} else if(c == ')') {
if(count == 0) {
return false;
}
count--;
}
}
return count == 0;
}
public:
vector<string> removeInvalidParentheses(string s) {
vector<string> res;
unordered_set<string> book;
queue<string> q;
q.push(s);
while(!q.empty()) {
string current_string = q.front();
q.pop();
if(book.find(current_string) != book.end()) {
continue;
}
book.insert(current_string);
if(isInvalid(current_string)) {
res.push_back(current_string);
} else if(res.empty()) {
for(int i = 0; i < current_string.size(); i++) {
if(current_string[i] == '(' || current_string[i] == ')') {
q.push(current_string.substr(0, static_cast<unsigned int>(i)) + current_string.substr(static_cast<unsigned int>(i + 1)));
}
}
}
}
return res;
}
};
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