Desicription
Given a Weather table, write a SQL query to find all dates’ Ids with higher temperature compared to its previous (yesterday’s) dates.
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+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------------+------------------+
|
For example, return the following Ids for the above Weather table:
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+----+
| Id |
+----+
| 2 |
| 4 |
+----+
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Solution
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SELECT
W1.Id
FROM
Weather W1, Weather W2
WHERE
W1.Temperature > W2.Temperature AND
TO_DAYS(W1.Date) - TO_DAYS(W2.Date) = 1
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