Desicription
输入一个整数数组，判断该数组是不是某二叉搜索树的后序遍历的结果。如果是则输出Yes,否则输出No。假设输入的数组的任意两个数字都互不相同。
Solution
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class {
private:
bool Verify(const vector<int>& sequence, int left, int right) {
if(sequence.empty()) {
return false;
}
int index = right - 1;
for(; index >= left; index--) {
if(sequence[index] < sequence[right]) {
break;
}
}
if(index < left) {
return true;
}
for(int i = index + 1; i < right; i++) {
if(sequence[i] < sequence[right]) {
return false;
}
}
for(int i = left; i <= index; i++) {
if(sequence[i] > sequence[right]) {
return false;
}
}
return Verify(sequence, left, index) && Verify(sequence, index + 1, right - 1);
}
public:
bool VerifySquenceOfBST(const vector<int> &sequence) {
return Verify(sequence, 0, sequence.size() - 1);
}
};
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