
CombinationSum
Given a set of candidate numbers (C) and a target number (T), find all unique
combinations in C where
the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
All numbers (including target) will be positive integers.
Elements in a combination must be in non-descending order.
The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7 and target 7,
A solution set is:
[7]
[2, 2, 3]
public class CombinationSum {
public ArrayList<ArrayList<Integer>> combinationSum(int[] candidates, int target) {
Arrays.sort(candidates);
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
ArrayList<Integer> list = new ArrayList<Integer>();
dfs(res, list, candidates, 0, 0, target);
return res;
}
public void dfs(ArrayList<ArrayList<Integer>> res, ArrayList<Integer> list,
int[] num, int pos, int sum, int target) {
if(sum == target)
res.add(new ArrayList<Integer>(list));
if(sum < target) {
for(int i = pos; i < num.length; i++) {
list.add(num[i]);
dfs(res, list, num, i, sum + num[i], target);
list.remove(list.size() - 1);
}
}
}
}




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