[leetcode] problem 509 – fibonacci number

The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,

F(0) = 0, F(1) = 1
F(N) = F(N - 1) + F(N - 2), for N > 1.

Given N, calculate F(N).

Example

No.1

Input: 2

Output: 1

Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.

No.2

Input: 3

Output: 2

Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.

No.3

Input: 4

Output: 3

Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.

Note

0 ≤ N ≤ 30.

Code

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
public int (int N) {
if (N < 2)
return N;

int a = 0;
int b = 1;

for (int i = 2; i <= N; i++) {
int sum = a + b;
a = b;
b = sum;
}

return b;
}