[leetcode] problem 92 – reverse linked list ii

Reverse a linked list from position m to n. Do it in one-pass.

Note

1 ≤ m ≤ n ≤ length of list.

Example

Input: 1->2->3->4->5->NULL, m = 2, n = 4

Output: 1->4->3->2->5->NULL

Code

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public class  {
int val;
ListNode next;
ListNode(int x) { val = x; }
}
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public ListNode reverseBetween(ListNode head, int m, int n) {
ListNode dummy = new ListNode(0);
dummy.next = head;
ListNode mPrevNode = dummy;

for (int i = 1; i < m; i++)
mPrevNode = mPrevNode.next;

ListNode mNode = mPrevNode.next;
ListNode nNode = mNode;
ListNode nPostNode = nNode.next;

for (int i = m; i < n; i++) {
ListNode next = nPostNode.next;
nPostNode.next = nNode;
nNode = nPostNode;
nPostNode = next;
}

mNode.next = nPostNode;
mPrevNode.next = nNode;

return dummy.next;
}