首页 > itarticle > [leetcode] problem 18 – 4sum

[leetcode] problem 18 – 4sum

admin 11月 13, 2020 0

Given an array nums of n integers and an integer target, are there elements a, b, c, and d in nums such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target.

Note

The solution set must not contain duplicate quadruplets.

Example

Given array nums = [1, 0, -1, 0, -2, 2], and target = 0.

A solution set is:

[
  [-1,  0, 0, 1],
  [-2, -1, 1, 2],
  [-2,  0, 0, 2]
]

Code

public List<List<Integer>> fourSum(int[] nums, int target) {
    List<List<Integer>> result = new ArrayList<>();

    Arrays.sort(nums);

    for (int i = 0; i < nums.length - 3; i++) {
        if (i > 0 && nums[i] == nums[i - 1])
            continue;

        threeSum(nums, target, nums[i], i + 1, result);
    }

    return result;

}

private void (int[] nums, int target, int num, int left, List<List<Integer>> result) {
    for (int i = left; i < nums.length - 2; i++) {
        if (i > left && nums[i] == nums[i - 1])
            continue;

        twoSum(nums, target, num, nums[i], i + 1, result);
    }
}

private void twoSum(int[] nums, int target, int num1, int num2, int left, List<List<Integer>> result) {
    int sum = target - num1 - num2;
    int right = nums.length - 1;

    while (left < right) {
        if (nums[left] + nums[right] == sum) {
            result.add(Arrays.asList(num1, num2, nums[left], nums[right]));
            left++;
            right--;

            while (left < right && nums[left] == nums[left - 1])
                left++;

            while (left < right && nums[right] == nums[right + 1])
                right--;
        } else if (nums[left] + nums[right] < sum)
            left++;
        else
            right--;
    }
}