[leetcode] problem 15 – 3sum

Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.

Note

The solution set must not contain duplicate triplets.

Example

Given array nums = [-1, 0, 1, 2, -1, -4],

A solution set is:

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[
[-1, 0, 1],
[-1, -1, 2]
]

Code

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public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> result = new ArrayList<>();

Arrays.sort(nums);

for (int i = 0; i < nums.length - 2; i++) {
if (i > 0 && nums[i] == nums[i - 1])
continue;

twoSum(nums, -nums[i], i + 1, nums.length - 1, result);
}

return result;
}

private void (int[] nums, int target, int left, int right, List<List<Integer>> result) {
while (left < right) {
if (nums[left] + nums[right] == target) {
result.add(Arrays.asList(-target, nums[left], nums[right]));
left++;
right--;

while (left < right && nums[left] == nums[left - 1])
left++;

while (left < right && nums[right] == nums[right + 1])
right--;
} else if (nums[left] + nums[right] < target)
left++;
else
right--;
}
}