513.find bottom left tree value

Tree, Medium

Question

Given a binary tree, find the leftmost value in the last row of the tree.

Example 1:

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Input:
2
/
1 3
Output:
1

Example 2:

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Input:
1
/
2 3
/ /
4 5 6
/
7
Output:
7

Note: You may assume the tree (i.e., the given root node) is not NULL.

Answer

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* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class {
public int findBottomLeftValue(TreeNode root) {
int res = 0;
if(root == null)
return -1;
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
while(!queue.isEmpty()){
int size = queue.size();
for(int i = 0; i < size; i++){
TreeNode node = queue.poll();
if(i == 0)
res = node.val;
if(node.left != null)
queue.offer(node.left);
if(node.right != null)
queue.offer(node.right);
}
}
return res;
}
}

Time complexity: O(n)