count and say

public class Solution{
	public String countAndSay(int n){
		if(n < 1)
		return "";
		
		String result = "1";
		while(n > 1){
			String temp = "";		//每求一个新的n，都得是从头开始
			char[] Array = result.toCharArray();
			for(int i = 0 ; i < Array.length ; i++){
				int count = 1;
				while(i+1 < Array.length && Array[i] == Array[i+1]){
					count++;
					i++;
				}
				temp = temp + count + Array[i];   //利用String的“+”特性
				result = temp;
			}
			n--;
		}
		return result;
	}
}