Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1
/
2 3
5
All root-to-leaf paths are:
- ["1->2->5", "1->3"]
Python Solution:
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def binaryTreePaths(self, root):
"""
:type root: TreeNode
:rtype: List[str]
"""
if not root: return []
path = []
res = []
def postorder(root, path, res):
path.append(str(root.val))
if not root.left and not root.right:
res.append('->'.join(path))
path.pop()
return
if root.left:
postorder(root.left, path, res)
if root.right:
postorder(root.right, path, res)
path.pop()
postorder(root, path, res)
return res
Summary:
- nothing to say.
LeetCode: 257. Binary Tree Paths
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