Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example:
- Given binary tree [3,9,20,null,null,15,7],
3
/
9 20
/
15 7
- return its level order traversal as:
[
[3],
[9,20],
[15,7]
]
Python Solution:
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def levelOrder(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if not root: return []
res = []
l = [root]
while l:
r = []
vals = []
for node in l:
vals.append(node.val)
if node.left: r.append(node.left)
if node.right: r.append(node.right)
res.append(vals)
l = r
return res
Summary:
- This should be a easy problem.
LeetCode: 102. Binary Tree Level Order Traversal
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