leetcode-794-tic-tac-toe

class :
    def validTicTacToe(self, board):
        """
        :type board: List[str]
        :rtype: bool
        """
        
        O = 0
        X = 0
        OOO = 0
        XXX = 0
        for i in range(3):
            # check row
            if board[i] == "OOO":
                O += 3
                OOO += 1
            elif board[i] == "XXX":
                X += 3
                XXX += 1
            else:
                for j in range(3):
                    if board[i][j] == "O":
                        O += 1
                    if board[i][j] == "X":
                        X += 1
            # check column
            if (board[0][i] == board[1][i]) and (board[2][i] == board[1][i]):
                if board[0][i] == "X":
                    XXX += 1
                if board[0][i] == "O":
                    OOO += 1
        # check diagnal                
        if (board[0][0] == board[1][1]) and  (board[1][1] == board[2][2]):
            if(board[1][1] == "X") :
                XXX += 1
            if(board[1][1] == "O") :
                OOO += 1
        if (board[2][0] == board[1][1]) and  (board[1][1] == board[0][2]):
            if(board[1][1] == "X") :
                XXX += 1
            if(board[1][1] == "O") :
                OOO += 1
        print(X,O,XXX,OOO)
        # key check part
        if XXX + OOO > 1:
            return False
        if (O > X) or (X > O + 1):
            return False
        if XXX == 1:
            if X != O + 1:
                return False
        if OOO == 1:
            if X != O:
                return False
        return True