c++拾遗-c++对表达式的增强

int main(int argc, const char * argv[]) {
    int a = 10;
    int b = 20;
    
    //返回一个最小数 并且给最小数赋值成30
    //该行报错 ，原因是C语言中表达式不可能做左值
    (a < b ? a : b ) = 30;
    
    printf("a = %d, b = %dn", a, b);
    return 0;
}

a = 30, b = 20
Program ended with exit code: 0