给定已排序数组，找出和为特定数值的两个数

- (void)fineTwoNumberWithArray0:(int *)nums count:(int)count target:(int)target {
    int leftNum,rightNum;
    
    for (int i = 0; i < count - 1; i++) {
        leftNum = nums[i];
        for (int j = i + 1; j < count; j++) {
            rightNum = nums[j];
            if ((rightNum + leftNum) == target) {
                NSLog(@"%d + %d = %d",leftNum, rightNum, target);
            }
        }
    }
}

- (void)fineTwoNumberWithArray1:(int *)nums count:(int)count target:(int)target {
    int left = 0;
    int right = count - 1;
    int sum = 0;
    while(left <= right) {
        sum = nums[left] + nums[right];
        if (sum < target) {
            left += 1;
        } else if (sum > target) {
            right -= 1;
        } else {
            NSLog(@"%d + %d = %d",nums[left], nums[right], target);
            left += 1;
            right -= 1;
        }
    }
}