Contents Leetcode 412 FizzBuzz 题目:输入一个数n,输出1-n,如果n能被3整除,输出Fizz;能被5整除,输出Buzz;同时能被整除,输出FizzBuzz 思路:直接遍历,先判断能被15整除,再判断能被3/5整除 1234567891011121314151617 func (n int) []string { res := make([]string, n) for i := range res { x := i + 1 switch { case x%15 == 0: res[i] = "FizzBuzz" case x%5 == 0: res[i] = "Buzz" case x%3 == 0: res[i] = "Fizz" default: res[i] = strconv.Itoa(x) } } return res} 赞微海报分享
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