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hdu 2055.an easy problem 题解代码

admin 11月 12, 2020 0

Problem ## Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should ## Output the result of y+f(x).

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output
for each case, you should the result of y+f(x) on a line.

Sample Input

6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output

19
18
10
-17
-14
-4

题解

做一个F函数，然后再调用就行了。
话说这题的字符是个坑，不能直接写scanf("%c %d")，会多读取回车，必须写成scanf("n%c %d")~

代码

#include<stdio.h>
int F(char c)
{
        if(c>=65&&c<=90) return c-64;
        else if(c>=97&&c<=122) return 96-c;
}
int main()
{
        int n,m,sum;
        char c;
        scanf("%d",&n);
        while(n--)
        {
                sum=0;
                scanf("n%c %d",&c,&m);
                sum=F(c)+m;
                printf("%dn",sum);
        }
        return 0;
}