Problem
Solution
Initial thoughts
Python implementation
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class : def isSameTree(self, p, q): """ :type p: TreeNode :type q: TreeNode :rtype: bool """ if p is None and q is None: return True if (p is None and q is not None) or (p is not None and q is None): return False if p.val != q.val: return False if self.isSameTree(p.left, q.left): return self.isSameTree(p.right, q.right) return False
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Java implementation
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* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class { public boolean isSameTree(TreeNode p, TreeNode q) { if(p==null && q==null){ return true; } if((p==null && q!=null) || (p!=null && q==null)){ return false; } if(p.val != q.val){ return false; } if(isSameTree(p.left, q.left)){ return isSameTree(p.right, q.right); } return false; } }
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Time complexity
O(n).
Space complexity
O(1).
Links
100. Same Tree
(中文版) 算法笔记: 力扣#100 相同的树
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