Problem
Solution
Analysis
Python implementation
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class : def tree2str(self, t): """ :type t: TreeNode :rtype: str """ if t is None: return '' if t.left is None and t.right is None: return str(t.val) if t.right is None: return str(t.val) + '({})'.format(self.tree2str(t.left)) return str(t.val) + '({})({})'.format(self.tree2str(t.left), self.tree2str(t.right))r
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Java implementation
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* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class { public String tree2str(TreeNode t) { if(t == null) return ""; if(t.left == null && t.right == null) return Integer.toString(t.val); if(t.right == null) return t.val + "(" + tree2str(t.left) + ")"; return t.val + "(" + tree2str(t.left) + ")" + "(" + tree2str(t.right) + ")"; } }
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Time complexity
O(n).
Space complexity
O(n).
Links
606. Construct String from Binary Tree
(中文版) 算法笔记: 力扣#606 根据二叉树创建字符串
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