leetcode.110 balanced binary tree

Title

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

Tag: Tree, Deep-first Search

Solution

判断一棵树是否为AVL树,也就是对于每个节点来说,判断当前节点的左右子树高度差的绝对值是否小与1。

如果小于1,说明当前节点为跟节点的树为AVL树。所以,很容易想到用递归求解。

下面直接贴上AC代码。

AC Code

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* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/

class Solution {
public:
bool (TreeNode* root) {
if(root == nullptr)
return true;
if(root->left == nullptr && root->right == nullptr)
return true;
if(abs(depth(root->left) - depth(root->right)) > 1)
return false;
return isBalanced(root->left) && isBalanced(root->right);

}
private:
int depth(TreeNode *root)
{

if(root == nullptr)
return 0;
return max(depth(root->left), depth(root->right)) + 1;
}
};