LeetCode p437 Path Sum III 题解
1.题目:
You are given a binary tree in which each node contains an integer value.
Find the number of paths that sum to a given value.
The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).
The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.
Example:
root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8
10
/
5 -3
/ 3 2 11 / 3 -2 1
Return 3. The paths that sum to 8 are:
5 -> 3
5 -> 2 -> 1
-3 -> 11
题意:
给一个树和一个目标数,求这个树从任意点开始有多少条路径可以得到目标数。
2.解题思路:
在每一个节点有四种向下的寻找方式,用set储存找过的节点。
3.代码
[title] [] [url] [link text]
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39
public class { public int target; public HashSet<TreeNode> hashSet; public int pathSum (TreeNode root, int sum) { target = sum; hashSet = new HashSet<TreeNode>(); return pathSum(root, sum, false ); } public int pathSum (TreeNode root, int sum, boolean hasparent) { if (root == null ) return 0 ; if (hashSet.contains(root) && !hasparent) return 0 ; if (!hasparent) hashSet.add(root); int count = sum == root.val ? 1 : 0 ; count += pathSum(root.left, sum - root.val, true ); count += pathSum(root.right, sum - root.val, true ); count += pathSum(root.left, target, false ); count += pathSum(root.right, target, false ); return count; } }
4.一些总结:
近期评论