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leetcode 350: intersection of two arrays ii

admin 11月 12, 2020 0

LeetCode Linked List

Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:

Each element in the result should appear as many times as it shows in both arrays.
The result can be in any order.

思路

代码

C语言版本：

int (const int* a, const int* b){
    return *a - *b;
}
 * Return an array of size *returnSize.
 * Note: The returned array must be malloced, assume caller calls free().
 */
int* intersect(int* nums1, int nums1Size, int* nums2, int nums2Size, int* returnSize) {
    qsort(nums1, nums1Size, sizeof(int), cmp);
    qsort(nums2, nums2Size, sizeof(int), cmp);
    int i = 0, j = 0, k = 0;
    int* intersect = (int*)malloc(sizeof(int)*(nums1Size+nums2Size));
    while ( i < nums1Size && j < nums2Size ) {
        if ( nums1[i] < nums2[j]) {
            i++;
        }else if ( nums1[i] > nums2[j] ) {
            j++;
        }else {
            intersect[k++] = nums1[i];
            i++;
            j++;
        }
    }
    *returnSize = k;
    return intersect;
}

60 / 60 test cases passed.
Status: Accepted
Runtime: 4 ms