
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)
You have the following 3 operations permitted on a word:
a) Insert a character
b) Delete a character
c) Replace a character
//dp[i][j]:表示A[0,i]和B[0,j]之间的最小编辑距离,//设A[0,i]形式str1c,B[0,j]形式str2d//1.c==d, dp[i][j] = dp[i-1][j-1];//2.c != d//2.1: c替换成d, dp[i][j] = dp[i-1][j-1] + 1;//2.2: append d, dp[i][j] = dp[i][j-1] + 1;//2.3: delete d, dp[i][j] = dp[i-1][j] + 1;int minDistance(string word1, string word2) { int len1 = word1.size(); int len2 = word2.size(); vector<vector<int> >dp(len1+1,vector<int>(len2+1,0)); //初始化 for(int i=0; i<=len1; i++){ dp[i][0] = i; } for(int i=0; i<=len2; i++){ dp[0][i] = i; } for(int i=1; i<=len1; i++){ for(int j=1; j<=len2; j++){ if(word1[i-1] == word2[j-1]){ dp[i][j] = dp[i-1][j-1]; } else{ dp[i][j] = min(dp[i-1][j-1],min(dp[i][j-1],dp[i-1][j]))+1; } } } return dp[len1][len2];}




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