[leetcode]551. student attendance record i

题目

You are given a string representing an attendance record for a student. The record only contains the following three characters:

‘A’ : Absent.
‘L’ : Late.
‘P’ : Present.

A student could be rewarded if his attendance record doesn’t contain more than one ‘A’ (absent) or more than two continuous ‘L’ (late).

You need to return whether the student could be rewarded according to his attendance record.

Example 1:

1 2	Input: "PPALLP" Output: True

Example 2:

1 2	Input: "PPALLL" Output: False

难度

Easy

方法

对'A'和'L'计数，如果'A'出现的次数>1，返回False；如果'L'连续出现的次数>2，则返回False；其他情况返回True

python代码

class (object):
    def checkRecord(self, s):
        """
        :type s: str
        :rtype: bool
        """
        a_count = 0
        l_count = 0
        for c in s:
            if c == "A":
                a_count += 1
                l_count = 0
                if a_count > 1:
                    return False
            elif c == "L":
                l_count += 1
                if l_count > 2:
                    return False
            else:
                l_count = 0

        return True

assert Solution().checkRecord("PPALLP") == True
assert Solution().checkRecord("PPALLL") == False
assert Solution().checkRecord("ALPP") == True

[leetcode]551. student attendance record i

题目

难度

方法

python代码

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