
Reverse a singly linked list.
常规解法和递归解法:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode reverseList(ListNode head) {
ListNode pre = null;
while (head!=null)
{
ListNode next = head.next;
head.next = pre;
pre=head;
head=next;
}
return pre;
}
public ListNode reverseList(ListNode head) {
return reverse(head,null);
}
private ListNode reverse(ListNode head,ListNode pre){
if(head == null) return pre;
ListNode next = head.next;
head.next = pre;
return reverse(next,head);
}
}




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