leetcode_062

Unique Paths II


Problem

给一个二维数组
求从左上角走到右下角的所有可能性

中间有一些路障。

Solution

代码如下

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
public class {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int m = obstacleGrid.length;
int n = obstacleGrid[0].length;
for(int i = 0; i < m; i++) {
if(obstacleGrid[i][0] == 1) {
obstacleGrid[i][0] = 0;
} else {
if(i-1>=0) {
obstacleGrid[i][0] = obstacleGrid[i-1][0];
} else {
obstacleGrid[i][0] = 1;
}
}
}
// 第一行如果有一个点有路障,后面都是0
// 这里可以从 1 开始
for(int i = 1; i < n; i++) {
if(obstacleGrid[0][i] == 1) {
obstacleGrid[0][i] = 0;
} else {
obstacleGrid[0][i] = obstacleGrid[0][i-1];
}
}
for(int i = 1; i < m; i++) {
for(int j = 1; j < n; j++) {
if(obstacleGrid[i][j] == 1) {
obstacleGrid[i][j] = 0;
} else {
// 动态规划
obstacleGrid[i][j] = obstacleGrid[i-1][j] + obstacleGrid[i][j-1];
}
}
}
// 最后要特别判断一下
if(obstacleGrid[m-1][n-1] == -1) {
return 0;
}
return obstacleGrid[m-1][n-1];
}
}

Over!