leetcode_508 Solution

Most Frequent Subtree Sum


求所有子二叉树的和,并且找出出现次数最多的那个和。也就是和的众数。

Solution

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public class {
Map<Integer, Integer> map = new HashMap<>();
public int[] findFrequentTreeSum(TreeNode root) {
List<Integer> res = new ArrayList<>();
getSum(root);
int max = 1;
for(int num : map.keySet()){
if(map.get(num) == max) {
res.add(num);
} else if (map.get(num) > max) {
res.clear();
max = map.get(num);
res.add(num);
}
}
// List 转 Array
int[] array = new int[res.size()];
for(int i = 0; i < res.size(); i++) {
array[i] = res.get(i);
}
return array;
}
// BFS 求合
private int getSum(TreeNode root) {
if(root == null) {
return 0;
}
int left = 0;
if(root.left != null) {
left = getSum(root.left);
}
int right = 0;
if(root.right != null) {
right = getSum(root.right);
}
int sum = root.val + left + right;
map.put(sum, map.getOrDefault(sum, 0) + 1);
return sum;
}
}