
题目描述
Given two strings s and t, write a function to determine if t is an anagram of s.
For example,
s = “anagram”, t = “nagaram”, return true.
s = “rat”, t = “car”, return false.
Note:
You may assume the string contains only lowercase alphabets.
Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?
代码
直接字符串排序,然后判断是否相等
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public class { public boolean isAnagram(String s, String t) { if(null == s) return null == t; return sort(s).equals(sort(t)); }
private String sort(String s){ char[] content = s.toCharArray(); Arrays.sort(content);
return new String(content); } }
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判断两个字符出现的字符和次数是否相等
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public class { public boolean isAnagram(String s, String t) {
if(s.length() != t.length() ) return false; int[] alphas = new int[26]; for(int i = 0; i < s.length(); i++) alphas[s.charAt(i) - 'a']++; for(int j = 0; j < t.length(); j++) alphas[t.charAt(j) - 'a']--; for(int alpha:alphas) if(alpha != 0) return false; return true; }
}
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