Problem Description:
The string “PAYPALISHIRING” is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: “PAHNAPLSIIGYIR”
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
题目大意:
给定一个字符串和一个要生成的行数,给出之字打印的结果。
Solutions:
很简单的字符串操作,利用一个辅助数组,存储每一行的结果,再依次连接起来即可。
Code in C++:
class Solution {
public:
string convert(string s, int numRows) {
if(s.empty()||numRows<1) return "";
if(numRows==1) return s;
vector<string> res(numRows);
int i = 0;
int j = 0;
int dif=1;
while(i<s.length())
{
res[j].push_back(s[i]);
if(j==numRows-1){
dif=-1;
}else if(j==0){
dif = 1;
}
j+=dif;
i++;
}
string ans="";
for(int i = 0;i<numRows;i++)
ans+=res[i];
return ans;
}
};
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