
Problem Description:
Given an integer (signed 32 bits), write a function to check whether it is a power of 4.
Example:
Given num = 16, return true. Given num = 5, return false.
Follow up: Could you solve it without loops/recursion?
题目大意:
给定一个32位的整数,判断它是否是4的幂。
Solutions:
Code in C++:
class Solution {
public:
bool isPowerOfFour(int num) {
while(num>1&&num%4==0)
{
num/=4;
}
return num==1;
}
};




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