
Problem Description:
Reverse a singly linked list.
题目大意:
反转一个单向链表
Solutions:
有许多方法可以反转一个单向链表,这里我们选择把每个结点都放在头结点之后一次,再从尾部连接头结点,最后再断环。
Code in C++:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* reverseList(ListNode* head) {
if(!head||!head->next) return head;
ListNode * current = head->next;
ListNode * next;
while(current->next)
{
next = current->next;
current->next=next->next;
next->next=head->next;
head->next=next;
}
current->next=head;
ListNode *newhead=head->next;
head->next=NULL;
return newhead;
}
};




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