Problem Description:
Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.
题目大意:
写一个函数,返回某一数字二进制表示中1出现的次数
Solutions:
利用位运算中&操作符号,和指定数的每一位都单独&一次,如果是1,则会返回1,再使用一个计数器实现统计。
Code in C++:
class Solution {
public:
int hammingWeight(uint32_t n) {
int count=0;
for(int i=0;i<32;i++)
if(n&1<<i) count++;
return count;
}
};
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