leetcode remove nth node from end of list

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增加头节点可以使结构更清晰,时间复杂度:O(N),空间复杂度:O(1)

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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {
ListNode* dummy = new ListNode(0);
dummy->next = head;
ListNode* fast = dummy;
ListNode* normal = dummy;
for(int i = 0; i < n; ++i) {
fast = fast->next;
}
while(fast->next != NULL) {
fast = fast->next;
normal = normal->next;
}
ListNode *tmp = normal->next;
normal->next = normal->next->next;
delete(tmp);
return dummy->next;
}
};