Given a string, you are supposed to output the length of the longest symmetric sub-string. For example, given “Is PAT&TAP symmetric?”, the longest symmetric sub-string is “s PAT&TAP s”, hence you must output 11.
Input Specification:
Each input file contains one test case which gives a non-empty string of length no more than 1000.
Output Specification:
For each test case, simply print the maximum length in a line.
Sample Input: Is PAT&TAP symmetric? Sample Output: 11
const int maxn = 1010; char S[maxn]; int dp[maxn][maxn];
int main(){ gets(S); int len = strlen(S), ans = 1; memset(dp, 0, sizeof(S)); //边界 for (int i = 0; i < len; i++) { dp[i][i] = 1; if (i < len - 1) { if (S[i] == S[i + 1]) { dp[i][i + 1] = 1; ans = 2; } } } //状态转移方程 for (int L = 3; L <= len; L++) { for (int i = 0; i + L - 1 < len; i++) {//枚举子串的起始结点 int j = i + L - 1;//子串右结点 if (S[i] == S[j] && dp[i + 1][j - 1] == 1) { dp[i][j] = 1; ans = L;//更新最长回文子串长度 } } } printf("%dn", ans); return 0; }
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