153. find minimum in rotated sorted array

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).

Find the minimum element.

You may assume no duplicate exists in the array.

Example 1:

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Input: [3,4,5,1,2] 
Output: 1

Example 2:

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Input: [4,5,6,7,0,1,2]
Output: 0
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class  {
public int findMin(int[] array) {
if (array == null || array.length == 0) {
return -1;
}
int lb = 0;
int ub = array.length - 1;
while (lb + 1 < ub) {
int mid = lb + (ub - lb) / 2;
if (array[mid] < array[ub]) {
ub = mid;
} else if (array[mid] > array[ub]){
lb = mid;
} else {
lb++;
}
}
return Math.min(array[lb], array[ub]);

}
}