34. find first and last position of element in sorted array

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given targetvalue.

Your algorithm’s runtime complexity must be in the order of O(log n).

If the target is not found in the array, return [-1, -1].

Example 1:

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Input: nums = [5,7,7,8,8,10], target = 8
Output: [3,4]

Example 2:

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Input: nums = [5,7,7,8,8,10], target = 6
Output: [-1,-1]
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class  {
public int[] searchRange(int[] nums, int target) {
int[] arr = {-1,-1};
if (nums == null || nums.length == 0) {
return arr;
}
int start = 0;
int end = nums.length - 1;
while (start <= end) {
if (nums[start] != target) {
start++;
} else {
arr[0] = start;
}
if (nums[end] != target) {
end--;
} else {
arr[1] = end;
}
if (arr[0] == start && arr[1] == end) {
return arr;
}
}
return arr;
}
}