88. merge sorted array

Description

Difficulty: Easy

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

题意:

给两个有序数组 nums1、nums2,将两个数组原地合并到 nums1,保持 nums1 有序。

Solution

与归并排序类似,但是从头部开始归并的成本太高,而 nums1 又有足够的长度,因此从两数组的尾部开始归并,放在 nums1 尾部(从 m + n - 1 开始)。

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class (object):
def merge(self, nums1, m, nums2, n):
"""
:type nums1: List[int]
:type m: int
:type nums2: List[int]
:type n: int
:rtype: void Do not return anything, modify nums1 in-place instead.
"""
if n == 0:
return
p1, p2 = m - 1, n - 1
for i in range(m + n - 1, -1, -1):
if p1 < 0:
nums1[i] = nums2[p2]
p2 -= 1
elif p2 < 0:
nums1[i] = nums1[p1]
p1 -= 1
elif nums1[p1] > nums2[p2]:
nums1[i] = nums1[p1]
p1 -= 1
elif nums1[p1] <= nums2[p2]:
nums1[i] = nums2[p2]
p2 -= 1