The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < $2^{31}$.
Example:
1
2
3
4
5
6
7
8
9
10
|
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
|
- 这里给定了是32位的数，对x异或y中的每一位进行累加即可
1
2
3
4
5
6
7
8
9
10
11
12
|
class (object):
def hammingDistance(self, x, y):
"""
:type x: int
:type y: int
:rtype: int
"""
count = 0
for i in range(32):
mask = 1 << i
count += 1 if ((x ^ y) & mask) > 0 else 0
return count
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
|
class (object):
def hammingDistance(self, x, y):
"""
:type x: int
:type y: int
:rtype: int
"""
if x == y:
return 0
xor = x ^ y
count = 0
while xor != 0:
if xor % 2 == 1:
count += 1
xor = xor // 2
return count
|
近期评论