a1100 mars numbers

People on Mars count their numbers with base 13:

• Zero on Earth is called “tret” on Mars.
• The numbers 1 to 12 on Earth is called “jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec” on Mars, respectively.
• For the next higher digit, Mars people name the 12 numbers as “tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou”, respectively.

For examples, the number 29 on Earth is called “hel mar” on Mars; and “elo nov” on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth and Mars number systems.

Each input file contains one test case. For each case, the first line contains a positive integer N (<100). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.

For each number, print in a line the corresponding number in the other language.

4 
29 
5 
elo nov 
tam 

hel mar 
may 
115 
13

#include <bits/stdc++.h>
using namespace std;


string unitDigit[13] = {"tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"};
// 13的[0,12]倍的火星文
string tenDigit[13] = {"tret", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"};

string num_to_str[170];         //数字 -> 火星文
map<string, int> str_to_num; //火星文 -> 数字
void init()
{
    //特殊处理
    for (int i = 0; i < 13; i++)
    {
        num_to_str[i] = unitDigit[i]; //个位为[0,12],十位为0
        str_to_num[unitDigit[i]] = i;
        num_to_str[i * 13] = tenDigit[i]; //个位为0,十位为[0,12]
        str_to_num[tenDigit[i]] = i * 13;
    }
    for (int i = 1; i < 13; i++) //十位
    {
        for (int j = 1; j < 13; j++) //个位
        {
            string str = tenDigit[i] + " " + unitDigit[j]; //火星文
            num_to_str[i * 13 + j] = str;                   //数字 -> 火星文
            str_to_num[str] = i * 13 + j;                   //火星文 -> 数字
        }
    }
}

int main()
{
    init();
    int N;
    scanf("%d%*c", &N);
    while (N--)
    {
        string str;
        getline(cin, str);
        if (str[0] >= '0' && str[0] <= '9') //数字
        {
            int num = 0;
            for (int i = 0; i < str.length(); i++)
                num = num * 10 + (str[i] - '0');
            cout << num_to_str[num] << endl;
        }
        else
            cout << str_to_num[str] << endl;
    }

    return 0;
}