反转链表

题目描述

输入一个链表,反转链表后,输出新链表的表头。

我的解答

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/*
public class ListNode {
int val;
ListNode next = null;

ListNode(int val) {
this.val = val;
}
}*/
public class Solution {
public ListNode ReverseList(ListNode head) {
if (null == head || null == head.next) {
return head;
}
ListNode prev = null;
ListNode next = null;
while (null != head) {
next = head.next;
head.next = prev;
prev = head;
head = next;
}
return prev;
}
}