Given an integer array, return the k-th smallest distance among all the pairs. The distance of a pair (A, B) is defined as the absolute difference between A and B.
Example:
Input:nums = [1,3,1] k = 1
Output: 0
Explanation:
Here are all the pairs:
(1,3) -> 2
(1,1) -> 0
(3,1) -> 2
Then the 1st smallest distance pair is (1,1), and its distance is 0.
Note:
2 <= len(nums) <= 10000.
0 <= nums[i] < 1000000.
1 <= k <= len(nums) * (len(nums) - 1) / 2.
cpp_code:
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class {
public:
intf_abs(int x){
return x > 0 ? x : -x;
}
intcount(vector<int>& nums, int mid){
int cnt = 0;
int n = nums.size();
int j = 0;
for(int i = 0; i < n; i++){
while(j < i && (nums[i] - nums[j]) > mid) j++;
cnt += (i - j);
}
return cnt;
}
intsmallestDistancePair(vector<int>& nums, int k){
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