Contents Problem 題目網址中文網址 Solution DP 建表。 Code UVa 10302 12345678910111213 int (){ long long ans[50001] = {}; for (int i = 1; i < 50001; i++) ans[i] = ans[i - 1] + (long long)i*i*i; int n; while (scanf("%d", &n) != EOF) printf("%lldn", ans[n]); return 0;} 赞微海报分享
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