
Problem Description:
Implement the following operations of a queue using stacks.
push(x) – Push element x to the back of queue.
pop() – Removes the element from in front of queue.
peek() – Get the front element.
empty() – Return whether the queue is empty.
Notes:
You must use only standard operations of a stack – which means only push to top, peek/pop from top, size, and is empty operations are valid.
Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
题目大意:
用栈实现队列的操作。
Solutions:
很简单,用两个栈即可取到任意一端的元素。
Code in C++:
class Queue {
stack<int> s1;
stack<int> s2;
public:
// Push element x to the back of queue.
void push(int x) {
s1.push(x);
}
// Removes the element from in front of queue.
void pop(void) {
while(!s1.empty())
{
s2.push(s1.top());
s1.pop();
}
s2.pop();
while(!s2.empty())
{
s1.push(s2.top());
s2.pop();
}
}
// Get the front element.
int peek(void) {
while(!s1.empty())
{
s2.push(s1.top());
s1.pop();
}
int p = s2.top();
while(!s2.empty())
{
s1.push(s2.top());
s2.pop();
}
return p;
}
// Return whether the queue is empty.
bool empty(void) {
return s1.empty();
}
};




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